Question

an object is placed at a distance of 'f' in front of convex mirror of focal Length 'f' find the magnification produced by it​

Answer 1

U=-2f

V=?

1/u+1/v=1/f

1/-2f + 1/v = 1 /f

1/v= 1/f + 1/2f

V = 2f/3

Now, m=-v/u

=-2f/3*-2f

=1/3

Answer 2

Given:

An object is placed at a distance of "f" in front of a convex mirror of focal length "f".

To find:

Magnification produced by it.

Calculation:

Applying Mirror Formula:

$\therefore \: \dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u}$

$= > \: \dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{( - f)}$

$= > \: \dfrac{1}{f} = \dfrac{1}{v} - \dfrac{1}{f}$

$= > \: \dfrac{1}{v} = \dfrac{1}{f} + \dfrac{1}{f}$

$= > \: \dfrac{1}{v} = \dfrac{2}{f}$

$= > v = \dfrac{f}{2}$

Magnification be m :

$m = - \dfrac{v}{u}$

$= > m = - \dfrac{ (\frac{f}{2}) }{ (- f)}$

$= > m = \dfrac{1}{ 2}$

So, magnification is ½.