Question

An object is placed at a distance of half the focal length of a convex lens. The image will be (a) at 2F, virtual and erect (b) at F, virtual and double in size (C) beyond 2F, real inverted (d) at F, real inverted
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Answer 1

Using Lens Formula , (1/f)=(1/v)−(1/u)

put f=f , u=−f/2

we get v=−f

As v is negative , the image is in the same side as of object so image is virtual because we have used a convex lens.

option b is correct

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