Question

An object is placed at a distances of 10cm from a diverging mirror of radius of curvature of 30cm . Find the position and nature of the image.

Answer 1

u=-10 cm for convex mirror, the object distance is -ve.

v=?

R= 30 cm

f =15 cm

ho= 5 cm

1/u+1/v=1/f

(-1/10)+(1/v)=(1/15)

1/v=1/15+1/10

1/v=(2+3)/30

1/v =5/30

v= 6 cm

size of the image

m= hi/ho =-v/u

=-6/10 =0.6

0.6=hi/5

hi=3 cm

The image is formed at a distance of 6 cm behind the mirror, virtual, upright and smaller than the object.

size of the image is 3 cm.

Answer 2

Ans - u=-10 cm for convex mirror, the object distance is -ve.
v=?
R= 30 cm
f =15 cm
ho= 5 cm
1/u+1/v=1/f
(-1/10)+(1/v)=(1/15)
1/v=1/15+1/10
1/v=(2+3)/30
1/v =5/30
v= 6 cm
size of the image
m= hi/ho =-v/u
=-6/10 =0.6
0.6=hi/5
hi=3 cm
The image is formed at a distance of 6 cm behind the mirror, virtual, upright and smaller than the object.

size of the image is 3 cm.