An object is placed at a distcance of 50cm in front of a concave mirror of
focal length 25cm. Find the image distance. If the object is 10cm high what
will be the nature and size of the image ?
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Answer:
u = -50 cm
f = -25 cm
h = 10 cm
v = ?
m = ?
Explanation:
use mirror formula:
1/v + 1/u = 1/f
1/v = 1/f - 1/ u
= 1/-25 - 1/-50
= 1/-25 + 1/50
= -2+1/50
1/v = -1/50
v = -50 cm
image distance = 50 cm
m = -v/u
= -(-50)/-50
= -1
therefore,the image is real,inverted and same size as the object.
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