Question

An object is placed at a height of 10m has mass 50kg calculate potential energy

Answer 1

Answer:

It is given that,

Mass of the object, m = 50 kg

The object is taken to a height of 4 meters above the ground.

Let P is the potential energy of the object. It is associated with the position of an object. It is given by :

P=mghP=mgh

P=50\times 9.8\times 4P=50×9.8×4

P = 1960 J

We need to find the kinetic energy of the object when it has fallen 2 meter. Let v is the final speed of the object. Firstly, it is required to find it as :

v^2-u^2=2asv

2

−u

2

=2as

a = g and u = 0

v^2=2gsv

2

=2gs

v^2=2\times 9.8\times 2v

2

=2×9.8×2

v = 6.26 m/s

Kinetic energy of the object when it has fallen 2 meters is :

K=\dfrac{1}{2}mv^2K=

2

1

mv

2

K=\dfrac{1}{2}\times 50\times (6.26)^2K=

2

1

×50×(6.26)

2

K = 979.69 J

So, the kinetic energy when it has fallen 2 meter is 979.69 J. Hence, this is the required solution.

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