an object is placed at distace 10 cm from the covex mirror of focal length 15 cm find its position nature of image
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Step-by-step explanation:
U= -10 cm
f= 15 cm
1/f = 1/v + 1/u
So, 1/v= 1/f - 1/u
1/v= 1/15 + 1/10
1/v = (2+3)/30 (lcm)
Therefore v=5/30 = 6 cm
Hence the image is formed behind the mirror and therefore it is virtual and erect
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