Question

An object is placed at distance
of 15 cm from a diverging mirror
of focal lenth 6 cm.

find nature
and position of the image
​

Answer 1

Explanation:

Given that

u= -15 cm

f= 6 cm

We need to find v

We know the formula

1/f = 1/v + 1/u

Therefore, 1/v= 1/f – 1/u

Substituting the known values in the above equation we get,

1/v= 1/6 + 1/15

1/v = (5+2)/30 (cm)

Hence v=30/7 = 4.28cm

v= 4.28cm

Nature of the image: The image is formed behind the mirror and it is virtual and erect.

Answer 2

Explanation:

I hope this will help you