Question

An object is placed at distance of 6 cm from a convex mirror of focal length 12 cm find the position and nature of the image ?

Answer 1

given u=-6 and f=+12

to find out v=-?

using mirror formula

1/v=1/f-1/u

1/v=1/12-1/-6

1/v=1/4

v=4cm behind the mirror

so nature of image is virtual

Answer 2

Answer:

Given:-

Distance of the object, (u) = -6 cm

Focal length, (f) = +12 cm

To Calculate:-

(a) Position of the image (v) = ???

(b) Nature of the image = ???

Solution:-

Formula to be used:-

⇒ $\frac{1}{f}=\frac{1}{v}+\frac{1}{u}$

or

⇒ $\frac{1}{u}=\frac{1}{f}+\frac{1}{u}$

Substituting the given values,

⇒ $\frac{1}{u}=\frac{1}{f}+\frac{1}{u}$

⇒ $\frac{1}{v}=\frac{1}{12}-(-\frac{1}{6})$

⇒ $\frac{1}{v}= \frac{1}{12}+\frac{1}{6}$

⇒ $\frac{1}{v}= \frac{1+2}{12}$

⇒ $\frac{1}{v}= \frac{3}{12}$

⇒ $v=4 \: cm$

(a) Position of the image (v) = 4 cm

(b) Nature of the image = virtual, erect and small in size.