Question

an object is placed at the distance of 30 cm in front of a convex lens of focal length 10 cm . find the position of the image ,its nature and magnification

Answer 1

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Answer 2

Position of image is 15 cm, real and inverted and magnification is (-0.5)

Explanation:

Given that,

Object distance from a convex lens, u = -30 cm

Focal length of the convex lens, f = +10 cm

Let v is the image distance. Using lens formula to find it as :

$\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{(10)}+\dfrac{1}{(-30)}\\\\v=15\ cm$

Magnification of lens is given by :

$m=\dfrac{v}{u}\\\\m=\dfrac{15}{-30}\\\\m=-0.5$

The formed image is real and inverted.

Learn more,

Lens formula

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