Question

an object is placed in front of a concave mirror of a radius or curvature is 40cm at a distance of 10cm . Find the position,nature, and magnification of the image​

Answer 1

Answer:

position of image is 20cm nature real magnification = 2

Answer 2

Solution:-

Distance of object u = - 40 cm.

Focal length of concave mirror f = - 20 cm.

By mirror formula

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

$or \: \frac{1}{v} = \frac{1}{f} - \frac{1}{u}$

∴

$\frac{1}{v} = \frac{1}{ - 20} - \frac{1}{( - 40)}$

$= \frac{1}{ - 20} + \frac{1}{40}$

$or \: v \: = - 40m$

Negative sign implies that image is in front of concave mirror,

hence image is real.

Magnification produced by concave mirror

$m = - \frac{v}{u} = - \frac{( - 40)}{( - 40)} =$

The image is of the same size and inverted.