an object is placed in front of a concave mirror of focal length 4 CM if the image is formed at 5 CM from the mirror find its object distance if the image is 4 CM high find the height of the object??
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here we have,
focal length, f= -4cm
image distance, v= 5cm
object distance, u=?
we have, mirror formula: 1/f = 1/v - 1/u
=>1/-4 = 1/5 -1/u
=>-1/u = -9/20
=> u = 20/9
now,-v/u= image height/object height
=>,-5/(9)20 = -4/ object height
=>object height= -25/9
focal length, f= -4cm
image distance, v= 5cm
object distance, u=?
we have, mirror formula: 1/f = 1/v - 1/u
=>1/-4 = 1/5 -1/u
=>-1/u = -9/20
=> u = 20/9
now,-v/u= image height/object height
=>,-5/(9)20 = -4/ object height
=>object height= -25/9
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Given:
The focal length of the mirror is f= 4 cm
The distance at which the image is made u=5 cm
Now height of image is hu= 4 cm
To find:
The height of the object.
Solution:
Using the mirror formula
1/f=1/v + 1/u
1/4=1/v + 1/5
1/4-1/5 = 1/v
v=20 cm
That is the object is placed .
Now hu/hv= u/v
4/ho=5/20
4×20/5=ho
ho=16 cm
The height of the object is 16 cm
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