Question

An object is placed in front of a concave mirror
of radius of curvature 15 cm, at a distance of
10 cm. The position and nature of the image
formed is
(a) + 30 cm, virtual and erect
(b) + 30 cm, real and inverted
(C) -30 cm, virtual and erect
(d) -30 cm, real and inverted​

Answer 1

Answer:

(d) -30 cm, real and inverted​

Explanation:

f = C/2= -7.5

u = -10

v= to find

1/f  = 1/u+ 1/v

1/-7.5 = 1/-10 + 1/v

-2/15 + 1/10 = 1/v

-4+3/30 = 1/v

-1/30 = v

-30 = v

-ve means real image

and as object is placed between focus and center of curvature so the image formed is inverted .

hope this helps