An object is placed in front of a convex lens with a focal length, f of 10 cm. What are the characteristics of the image formed if the object distance is 15 cm?
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Question:
- An object is placed in front of a convex lens with a focal length, f of 10 cm. What are the characteristics of the image formed if the object distance is 15 cm?
Information provided with us:
- Focal length at which object is placed is of 10cm
- Object distance is 15 cm
What does we have to calculate:
- We have to calculate the image distance and the nature of image formed.
Remember that,
- Object distance is u
- focal length is f
Formula needs to be used:
Lens Formula:-
- 1/v - 1/u = 1/f
Also remember that u is negative.
Linear magnification:-
- m = length of image (I) / length of object (O)
Or,
- m = v/u
Evaluating the values,
- Here we are evaluating the values in the first formula which is lens formula.
=> 1/v - 1/-15 = 1/10
- We know that, by multiplying minus sign with minus sign we gets plus.
=> 1/v + 1/15 = 1/10
- Transposing 1/15 from L.H.S. to R.H.S. it would be negative.
=> 1/v = 1/10 - 1/15
- Taking L.C.M.,
=> 1/v = (1×3 / 10×3) - (1×2 / 15×2)
=> 1/v = 3/30 - 2/30
=> 1/v = (3-2/30)
- On subtracting 3 with 2 we gets 1,
=> 1/v = 1/30
- On cross multiplying,
=> v = 30
_________________
- Here we are evaluating the values in the above given second formula of linear magnification,
=> m = 30/15
- Cancelling by 5,
=> m = 6/3
- Cancelling by 3,
=> m = 2
________________
- Characteristics of image is inverted and real and distance of image is of 30 cm
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