an object is placed in front of a coverging lens in such a position that the lens (F=13 cm)creates a real image located 24cm from the lens. then with the object remaining in place ,the lens is replaced with another converging lens (f=17 cm).a new image real image is formed what is the image distance of new image
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case-1
f=13cm v=24cm u=?
1/f=1/v-1/u
1/u=1/v-1/f
1/u=1/24 -1/13
1/u -11/13*24
u= -13*24/11
u=- 28.36cm.
now for the second condition
f=17cm u=28.36cm
1/f =1/v-1/u
1/v=1/17 -1/28.36
1/v =11.36/17* 28.36
v=42.44cm
So the new image distance is 42.44 cm
f=13cm v=24cm u=?
1/f=1/v-1/u
1/u=1/v-1/f
1/u=1/24 -1/13
1/u -11/13*24
u= -13*24/11
u=- 28.36cm.
now for the second condition
f=17cm u=28.36cm
1/f =1/v-1/u
1/v=1/17 -1/28.36
1/v =11.36/17* 28.36
v=42.44cm
So the new image distance is 42.44 cm
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