Question

an object is placed in front of cancave mirror of focal length 10cm if image is formed is double the height of object find out position of object from pale of mirror ​

Answer 1

$\sf h_e=2h_o \\\\\sf </p><p>=\frac{h_e} {h_o}=2 = \frac{v} {u} \\\\\sf </p><p>=v=2u \\\\\sf </p><p>Now, \: by \: mirror \: formula, \\\\\sf </p><p>\frac{1}{f}= \frac{1}{v}+ \frac{1}{u} \\\\\sf </p><p>\frac{1}{-10}= \frac{1}{2u}+ \frac{1}{u} \\\\\sf </p><p>\frac{1}{-10}= \frac{3}{2u} \\\\\sf </p><p>2u=-30 \\\\\sf </p><p>u= - 15 cm \\\\\sf </p><p></p><p>Hence, the \: object \: is \: 15 \: cm \: away \: from \: the \: pole.$