an object is placed in front of concave mirror of focal length 20 cm.the mage formed is 3 times the size of object. calculate 2 possible distances of objecct from the mirror.
Answers
Answered by
5
Simple
Given , f= -20
m = +3 or -3 (two different positions)
m = -v/u
3= -v/u
v = -3u. [1]
1/f=1/v+1/u
thus, 1/-20 = 1/-3u + 1/u. ( from 1 replacing v)
1/-20 = 2/3u
3u = -40. (Cross multiplying)
u= -40/3
Now if m = -3
m = -v/u
-3 = -v/u
v= 3u. [2]
1/f= 1/v + 1/u
1/-20= 1/3u + 1/u. (Replacing v by [2])
1/-20=4/3u
3u = -80
u= -80/3 cm
Thus the two positions are -40/3 cm and -80/3 cm
Given , f= -20
m = +3 or -3 (two different positions)
m = -v/u
3= -v/u
v = -3u. [1]
1/f=1/v+1/u
thus, 1/-20 = 1/-3u + 1/u. ( from 1 replacing v)
1/-20 = 2/3u
3u = -40. (Cross multiplying)
u= -40/3
Now if m = -3
m = -v/u
-3 = -v/u
v= 3u. [2]
1/f= 1/v + 1/u
1/-20= 1/3u + 1/u. (Replacing v by [2])
1/-20=4/3u
3u = -80
u= -80/3 cm
Thus the two positions are -40/3 cm and -80/3 cm
ShanAgrawal:
wlcm dear
Similar questions