Question

an object is placed in front of the length L at a distance d of its bisector line an observer is at a perpendicular distance of 2d from that mirror if the observer is walking parallel to the mirror, upto what maximum possible distance he can observe the image of that object
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Answer 1

Explanation:

To find : Maximum distance walked by observer until he see the object in the mirror=?

The maximum distance walked can be shown in the figure below:

X=L+2x

From geometry of similar triangles,

p

x

=

d

L/2

x=

2d

Lp

So X=L+2x

=L+2×

2d

Lp

X=L(1+

d

p

)