Question

an object is placed in the front of convex mirror of radius of curvature 20cm its image is formed 8 cm behind the mirror find the distance of the object from the mirror

Answer 1

hope it helps i think......

Answer 2

Answer:

Required image distance is -40 cm.

Explanation:

Given, radius of curvature $= 20 \: cm$

Image distance $= 8 \: cm$

We know,

$Focal \: \: length = \frac{Radius \: of \: curvature }{2} = \frac{20}{2} = 10 \: cm$

Again,

$\frac{1}{u} + \frac{1}{v} = \frac{1}{f}$

$u= Object \: \: distance,v= Image \: \: distance ,f=Focal \: \: length$

Now,

$\frac{1}{u} + \frac{1}{8} = \frac{1}{10}$

$\frac{1}{u} = \frac{1}{10} - \frac{1}{8} = \frac{4 - 5}{40} = \frac{ - 1}{40}$

→$u = - 40$

Required image distance is -40 cm.