Question

.An object is placed on the principal Axis at a distance of 8 cm in front of the concave mirror of focal length 3 cm draw...​

Answer 1

Answer:

$u = 8cm \\ f = 3cm \\ v = \\ \\ \frac{1}{u} + \frac{1}{v} = \frac{1}{f } \\ \frac{1}{8} + \frac{1}{v} = \frac{1}{ 3 } \\ \frac{1}{v} = \frac{1}{3} - \frac{1}{8} \\ \frac{1}{v} = \frac{8 - 3}{24} \\ \frac{1}{v} = \frac{5}{24} \\ v = \frac{24}{5} = 4.8$