Question

an object is placed on the principal axis of a concave mirror of focal length 24 cm if the image distance is 20 CM more than the object distance, the magnification of the images is​

Answer 1

The magnification of the image is 1.5.

Explanation:

Given that,

Focal length of the concave mirror, f = -24 cm (it is negative for concave mirror)

Let u is the object distance and v is the image distance. According to given condition, the image distance is 20 m more than the object distance,

v = 20 + u

We can find the object distance from the mirror using mirror's formula as :

$\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}$

$\dfrac{1}{20+u}+\dfrac{1}{u}=\dfrac{1}{-24}$

u = -8 cm

Image distance becomes,

v = 20 + (-8)

v = 12 cm

The magnification of the mirror is given by :

$m=\dfrac{-v}{u}$

$m=\dfrac{-12}{-8}$

m = 1.5

So, the magnification of the image is 1.5. Hence, this is the required solution.

Learn more

https://brainly.in/question/14528340

Mirror's formula

Answer 2

Answer:

Explanation:

Given that:

f = -24 cm (it is negative for concave mirror)

• Let u is the object distance and v is the image distance.
• According to given condition, the image distance is 20 m more than the object distance.

v = 20 + u

• We can find the object distance from the mirror using mirror's formula.

u = -8 cm

• Image distance becomes.

v = 20 + (-8)

v = 12 cm

• The magnification of the mirror is given by :

m = -v/u

m= -12/-8

m = 1.5

Also learn more

The radius of curvature of a spherical mirror is 20 cm .what its focal length?

https://brainly.in/question/312220