Question

An object is placed on the principal axis of a concave mirror of focal length equal to 10 cm, at a distance of about 15 cm from it's pole. Find the position and nature of the image.

Answer 1

Answer:

The Lens/Mirror formula is

1/u + 1/v = 1/f

u = +15 and f = +10 (both Real distances, hence +)

1/15 + 1/v = 1/10

1/v = 1/10 - 1/15 = 6/60 - 4/60 = 2/60 = 1/30

v = +30

so a real image 30cm from the mirror.

M = v/u = +2 so the image is twice the size of the object. M>0 so inverted.