an object is placed on the principal axis of a convex Lens of focal length 10 cm. if the distance of the object from the lens is 30 cm, what is the distance of the image formed?
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Answered by
4
f=10cm
u=-30cm
1/f=(1/v)-(1/u)
1/10=(1/v)+(1/30)
1/v= (1/10)-(1/30)
v= 15cm
Answered by
8
f = 10cm
u = -30 cm
lens formula:
1/v - 1/u = 1/f
1/v = 1/f + 1/u
1/v = 1/10 - 1/30
1/v = 3-1/30
1/v = 2/30
1/v = 1/15
v = +15 cm
sp the image is formed 15 cm on the other side of the lens...it means it is between c2 and f2.
hope it helps
kindly mark it brainliest.
vatsrahul:
why u took u = -ve?
coz u is always negative for both mirror and lens
of both types, concave and convex
ok thanks
and what about focal length?
and distance of image (v)
You should learn the Cartesian sign
Well focal length is negative for convex mirror and concave lens
ok
thanks Ankita for your Help
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