Question

An object is placed perpendicular to the principal axis of a concave lens of focal length 10cm. The distance of the object from the lens is 15cm. Find the nature,position and magnfication of lens

Answer 1

Answer:

Given: Object height, h =+5 cm

Focal length, f = -10 cm

Object distance, u = -20 cm

Applying the lens formula:

Putting values

V=-6.67 cm

Now height of image can be calculated as follows:

therefore, the image formed will be virtual, eract and diminished in size.