Question

An object is placed perpendicular to the principal axis of a convex lens of focal length 20cm the distance of the object from the length is 30 cm find the position second the magnification third the nature of the image formed.

Answer 1

Explanation:

From lens formula, 

v1−u1=f1

u = - 20 cm

Focal length = -30 cm

∴v1=−301+(−20)1

⇒v1=600−20−30=600−50=−121

⇒v=−12 cm