An object is placed perpendicular to the principal axis of a convex lens of focal length 4 cm. The distance of the object from the lens is 6 cm. Find the position and nature of the image.
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Given - f=+24cm,u=−16cm ,
As ∣u∣(16cm)<∣f∣(24cm) ,it means object lies between F and C , in this position of object the rays from object cannot meet at any point on the other side of lens ,which is also clear from the position of image found below ,
From lens equation v=
u+f
uf
=
−16+24
−16×24
=−48cm ,
-ive sign shows that image will be formed on the same side of lens , where the object is placed .
Now linear magnification m=I/O=v/u=−48/−16=+3 ,
or I=3×4=12cm (given O=4cm) ,
since m=+ive and m>1 ,therefore image will be virtual ,erect and magnified
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