An object is placed upright on the axis of a thin convex lens at a distance of four focal lengths (4f) from the center of the lens. An inverted image appears at a distance of 4/3 f on the other side of the lens. What is the ratio of the height of the image of the height of the object?(a) 1/3(b) 3/4(c) 4/3(d) 3/1
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Answer:
a) 1/3
Explanation:
Focal length of the object = 4f ( Given)
Distance of inverted image = 4/3f ( Given)
Magnification = f/d0
where f is the focal length of the lens and d0 is the object distance, hence
= -(4/3f/4f)
= - 1/3
Alternatively, M = - image distance/object distance
= - 4f/3 x 1/4f
= -1/3
The image formed will be an inverted image. Thus, the ratio of the height of the image of the height of the object is 1/3.
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