An object is placed vertically at a distance of 20 cm from a convex lens. If the height of the
object is 5 cm and the focal length of the lens is 10 cm, What will be the position, size and
nature of the image? How much bigger will the image be as compared to the object?
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Answer:
Given, u=-20cm
f=10cm
v=?
We know
f
1
=
v
1
−
u
1
10
1
=
v
1
−
20
(−1)
v
1
=
20
2−1
v=20cm
We know
magnification (M)=
h
o
h
i
=
u
−v
or,
−20
20
=−1=
h
o
h
i
since,h
0
=5cm
so,h
i
=−5cm
nature = real image
Explanation:
hope it was helpfull❤️
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