An object is placed vertically at a distance of 20 cm from a convex lens. If the height of the object is 5 cm and the focal length of the lens is 10 cm, what will be the position, size and nature of the image? How much bigger will the image be as compared to the object?
Answers
We clearly know that, for finding a quadratic polynomial with sum of zeroes = S, and product of zeroes = P, we use equation ::
\Large\boxed{\bf{p(x) = x^2 - Sx + P}}
p(x)=x
2
−Sx+P
\:
\underline{\sf{\bigstar\:Putting\:all\:known\:values\:::}}
★Puttingallknownvalues::
\begin{gathered}\\ \quad \longrightarrow \quad \sf p(x) = x^2 - \bigg(\dfrac{9}{2}\bigg)x + 2 \end{gathered}
⟶p(x)=x
2
−(
2
9
)x+2
\:
\underline{\sf{\bigstar\:Multiplying\:the\:equation\:with\:2\:::}}
★Multiplyingtheequationwith2::
\begin{gathered}\\ \quad \longrightarrow \quad \sf p(x) = 2\Bigg(x^2 - \bigg(\dfrac{9}{2}\bigg)x + 2\Bigg) \end{gathered}
⟶p(x)=2(x
2
−(
2
9
)x+2)
\begin{gathered}\\ \quad \longrightarrow \quad \sf p(x) = \big(2\:\times\:x^2\big) - \bigg(\dfrac{9}{\cancel{2}}\:\times\:\cancel{2}\bigg)x + \big(2\:\times\:2\big)\end{gathered}
⟶p(x)=(2×x
2
)−(
2
9
×
2
)x+(2×2)
\begin{gathered}\\ \quad \longrightarrow \quad \large \bf 2x^2 - 9x + 4\end{gathered}
⟶2x
2
−9x+4
\:
\therefore\:{\underline{\sf{Hence,\:required\:polynomial\:is\:\bf{2x^2 - 9x + 4}}}}∴
Hence,requiredpolynomialis2x
2
−9x+4
\:
\LARGE\underline{\underline{\textsf{\textbf{Explore\:More\::-}}}}
ExploreMore:-
\:
If α and β are zeroes of the quadratic polynomial ax² + bx + c, then α + β = -b/a and αβ = c/a.
If α, β, γ are the zeroes of cubic polynomial ax³ + bx² + cx + d, then α + β + γ = -b/a, αβ + βγ + γα = c/a and αβγ = -d/a.
\:
\LARGE\underline{\underline{\textsf{\textbf{Learn\:more\:on\:brainly\::-}}}}
Learnmoreonbrainly:-
\:
\underline{\sf{\bigstar\:Question\:::}}
★Question::
\:
Find zeroes of the quadratic polynomial 4x² - x - 5 and verify relationship between it's zeroes and coefficients.
\:
\underline{\sf{\bigstar\:Answer\:::}}
★Answer::
\:
https://brainly.in/question/429646
Answer:
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