Question

an object is planed in front of conceve mirror focal length15cm inverted image is height is6cm observed at distances 37.5from mirror find distances its height​

Answer 1

Answer:

the object is 25cm behind the mirror and its height is 3cm

explanation:

by mirror formula

1/f=1/v + 1/u

1/-15=1/-37.5 + 1/u

1/u=1/37.5-1/15

1/u=(1-2.5)/37.5

1/u=-1.5/37.5

u=37.5/1.5

u=25cm

h'/h=-v/u

-6/h=-(-37.5)/25

h=3cm

Answer 2

Answer:

given,

height of image,h'=6cm

focal length,f= -15 cm

image distance,v= -37.5 cm

object distance ,u =?

object height ,h =?

we have,

1/v + 1/u =1/f

1/u =1/f -1/v

= -1/15 + 1/37.5

=0.67 +0.27

1/u =0.94

u = 1/0.94

=1.06 cm

again,

we have,

h'/h = -v/u

6/h =37.5/1.06

35.38h =6

h=6/35.38

=0.17cm

therefore,

reqd. object distance=1.06cm

object height=0.17cm