Question

An object is projected at an angle 60° with respect to the horizontal The initial velocity of the object is 10 ms-1. The maximum height reached by the object is
(g = 10 ms-2
(A) 2.5 m
(B) 3.75 m
(C) 1.5 m
(D) 3.2 m​

Answer 1

Maximum height reached by the object is 3.75

Answer 2

H = u^2 (sin^2 θ)/2g
H = 10^2 (sin^2 60)/2(10)
H = 100 (√3/2)^2 / 20
H = 100 (3/4) /20
H= 3.75m
Option b is correct.

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