An object is projected at an angle of elevation of 450 with a velocity of 100 m/s. Calculate its ?
(i) range
(ii) time of flight
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a particle is projected at an angle of elevation 45° with velocity 100 m/s
(1) Range = u²sin2∅/g
=(100)² ×sin 2× 45°/10 { g = 10 m/s²
=(10000) × 1/10 = 1000 m
(2) time of flight = 2u.sin∅/g
= 2× 100 × 1/√2/10
= 10√2 sec
(1) Range = u²sin2∅/g
=(100)² ×sin 2× 45°/10 { g = 10 m/s²
=(10000) × 1/10 = 1000 m
(2) time of flight = 2u.sin∅/g
= 2× 100 × 1/√2/10
= 10√2 sec
ani47:
tq
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