Physics, asked by Dikey, 1 year ago

An object is projected at an angle of elevation of45° with velocity of 100m/s calculate is range and time of flight

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Answered by Anonymous
1
angle =45 and velocity =100 m/s and hence range =u^2sin2@/g =100x100 xsin45x2/10=1000m and time of flight=2usin@/g =2x100x1/root2x10=20/root2=10root2 seconds =10x1.4142=14.142 seconds ...hope it will help u

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