An object is projected at angle of 60°; with the horizontal, with kinetic energy K. Its kinetic energy at maximum height is ....... (A) 0 (B) K (C) K4 (D) K2
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Explanation:
let u be the initial velocity.
initial kinetic energy isK=(
2
1
)mu
²
at the maximum height velocity isucos60=(
2
u
)
kinetic energy at the maximum height isKE=(
2
1
)m(
2
u
)²
=(
4
1
)k
Answer C:
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