Question

An object is projected from ground with speed
20 m/s at angle 30° with horizontal. Its centripetal
acceleration one second after the projection is
[Take g = 10 m/s2)
(1) 10 m/s2
(2) Zero
(3) 5 m/s2
(4) 12 m/s2​

Answer 1

Explanation:

Please find below the solution to the asked query:

Given that the initial velocity of the particle is 20

m/s and the angle of projection is 300. Let the velocity of the object after t = 1 secis v. Therefore,

v cos a=u cos V cos a=20 cos 30

v cos a=103v.v sin a=v2-300-----

-v&v sin a=u sin 0-gt 20 sin 30-10x1=v2-300-

-----V=V2-300=0= v=1037 ms/

So, the particle will be at its highest point. Therefore the centripetal acceleration is g as shown in the figure below.

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