Question

An object is projected horizontally from a top of the tower of height h. The line joining the point of projection and point of striking on the ground makes an angle 45 degrees with ground. Then with what velocity the object strikes the ground??​

Answer 1

Answer:$\sqrt\\ 5gh/2$

Explanation:

Tan θ=hR, R = u 2hg−−√,V=u2+2gh−−−−−−−√  

tanΘ= h/r

=> r=$\sqrt\\u/2hg$

=> v= $\sqrt\\u^{2}+2gh$

=$\sqrt5gh/2$

hope it helps