Question

An object is projected upward making an angle of 40° with the horizontal with an initial speed of 50m/s, how far from the point of projection will the object strike ? *​

Answer 1

Answer:

433 m                                                                                                                                                                                                              

Explanation:

vx = v cos theta                                vy = v sin theta

    = 50 cos 30°                                     = 100 sin 30

    = 43.30                                             = 50

Total time

vf = vi + at    NOTE : vi = vy

0 = 50 + -10 t

-50 = -10 t

-50/-10 = -10 t/ -10

5 = t

Range ( horizontal distance )

R = vx . Tt ( total time = t .2)

  = 43.30 . 5(2)

  = 43.30 . 10

   = 433 m

please mark as brainliest