Question

an object is projected vertically upward with a velocity of 60m/s.Calculate the distance travelled in 4th second.

Answer 1

time=4second. acceleration=-9.8m/secondsquare
initial speed=60m/s
ut+1/2atsquare=distance
60×4+1/2×9.8×4×4=s
s=240+4.9×16
s=please u calculate from here u will get answers
i hope it will help you