Physics, asked by venkannathati, 8 months ago

An object is projected vertically upwards with a velocity 20m/s Find the maximum height reached by the body. (take g=10m/s)​

Answers

Answered by Anonymous
10

Answer:

\sf{The \ maximum \ height \ reached \ by \ the}\sf{body \ is \ 20 \ m}

Given:

  • Initial velocity (u)=20 m/s

  • Acceleration due to gravity (a)=10 m/s²

To find:

  • The maximum height (s) reached by the body.

Solution:

\sf{The \ object \ in \ moving \ opposite \ to \ gravity.}

\sf{\therefore{Final \ velocity (v)=0}}

\sf{Acceleration \ due \ to \ gravity=-g=-10 \ m \ s^{2}}

\sf{According \ to \ the \ third \ equation \ of \ motion.}

\sf{\mapsto{v^{2}=u^{2}+2as}}

\sf{\mapsto{\therefore{0^{2}=20^{2}+2(-10)s}}}

\sf{\mapsto{\therefore{0=400+2(-10)s}}}\sf{\mapsto{\therefore{2(-10)s=-400}}}

\sf{\mapsto{\therefore{s=\dfrac{400}{20}}}}

\sf{\mapsto{\therefore{s=20 \ m}}}

\sf\purple{\tt{\therefore{The \ maximum \ height \ reached \ by \ the}}}

\sf\purple{\tt{body \ is \ 20 \ m}}

Answered by Anonymous
7

\rule{200}2

\huge\bold{\mathtt{\underline{\underline{QUESTION}}}}

➠ An object is projected vertically upwards with a velocity 20m/s Find the maximum height reached by the body. (take g=10m/s) .

\rule{200}2

\huge\bold{\mathtt{\underline{\underline{ANSWER}}}}

{\red\bigstar\large\bold{\mathrm{\green{\underline{Given:}}}}}

\sf Initial\:velocity \:=\: 20\: m/s

\sf g\:=\:-\:10\:{m/s}^{2}

\sf g\:will \:be\:taken\:-ve\:here \\ \sf because\:it\:is\:thrown\:upward

{\red\bigstar\large\bold{\mathrm{\green{\underline{To\:Find:}}}}}

\sf Maximum\:height \:reached\:by\:the\:body\:(s)

{\red\bigstar\large\bold{\mathrm{\green{\underline{Solution:}}}}}

\sf v\:=\:0

\huge\bold{\textsf{\underline{\underline{\red{Formula\:used}}}}}

\large\boxed{\pink{\mathtt{ {v}^{2}\:-\:{u}^{2}\:=\:2as}}}

\large\bold{\orange{\mathtt{ {0}^{2}\:-\:{20}^{2}\:=\:2(-10)s}}}

\large\bold{\orange{\mathtt{-400\:=\:-20s}}}

\large\bold{\orange{\mathtt{ s\:=\: \dfrac{-400}{-20}}}}

\large\bold{\orange{\mathtt{ s\:=\:20\:m}}}

\large\bold{\red{\underline{Maximum\:height\:reached\:=\:20\:m}}}

\rule{200}2

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