Question

An object is projected with a vellocity of 40m/sec. find max hieght attend by object , time taken to reach max hieght and vellocity after 3 secs

Answer 1

Maximum height = u²/2g = 40 x 40 /2 x 10  m = 80 m (Ans)

Time taken = u/g = 40/10 s = 4 s (Ans)

Velocity after 3 s = u - gt = 40 - 30   m/s = 10 m/s (Ans)