an object is projected with a velocity of 20 metre per second making an angle of 45 degree with horizontal the equation for the trajectory is h=Ax -Bx² where it is height exercise until distance A and B are constants the ratio of A:B is
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your ans for this question is 2√2:1 for A:B
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compare this equation
h=xtanθ-gx²/2u²cos²θ
h=Ax-Bx²
A=tanθ
B=g/2u²cos²θ
A/B=(tanθ)(2u²cos²θ)/g
=2u²sinθcosθ/g
=2×20²sin45°cos45°/10
=2×400×1/√2×1/√2/10
=40m
kahkashans31:
thanks
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