An object is projected with a velocity of 50 m /s at an angle θ to f the vertical if the total time of flight of the projectial is 5sec what you is the value of θ
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Given :-
Velocity of body = u = 50 ms-¹
Angle of Projection = Ø
Total time of flight of body = 5 s
We are asked to find the value of angle of Projection.
As we know a relation,
Time of Flight = 2u sinØ/g
5 = 2 × 50 × sinØ/ 10
5 × 10 / 100 = sinØ
sinØ = 1/2
sinØ = sin 30°
Ø = 30°
Hence,
The angle of Projection = Ø = 30°.
Some formulas of this chapter,
1. Horizontal Range = R = u² sin 2Ø/g
2. Maximum height= H = u sinØ/2g
3. Trajectory equation = y = x tanØ - gx²/2u²cos²Ø
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