Question

An object is projected with a velocity square root of 8gR/3 form earth.The velocity of the object at the maximum height will be

Answer 1

Answer is 0ms-1. because at maximum height all the kinetic energy is converted to potential energy

Answer 2

Answer:

√2/3gR

Explanation:

Escape velocity from earth's gravitational field Ve = √2gR

Velocity of the projection V = √8/3gR

=√2.66gR

Since velocity of projection is greater than escape velocity the objects travels out of the earth's gravitational field with velocity V'

V' = √V²-Ve²

V' = √8gR/3-2gR

V' = √2/3gR