Question

an object is projected with velocity of 40 m/s at an angle of 45 tho the horizontal . air resistance is negligible .what is the speed of the object after 5.00s​

Answer 1

By equations of motion,

V = U+at

V = [40 cos45 (i) + 40 sin45 (j)] + [g (-j) . 5]

V = 40/√2(i) + 40/√2(j) - 50(j)

V = 28.28(i) + 28.28(j) - 50(j)

V = 28.28(i) - 21.72(j)

V = √(28.28)²+(21.72)²

V = 35.65 m/s