Physics, asked by Akashdas33, 1 year ago

An object is protected at an angle of elevation of 45° with a velocity of 100m/s . calculate it's

1. Range
2. Time of flight

Answers

Answered by abhi178
0
Range =u^2sin2@/g
=(100)^2sin2 (45)/g
=10000/10 {let g=10m/sec^2
=1000m
time of flight=2usin@/g
=2 (100) sin45/10
=10root2 sec
Similar questions