Question

an object is punted at 25.0 m/s (40.0° n of e) on g's home planet. what is the range (x distance) of the object on level ground? (use g = 18.0 m/s2)

Answer 1

Given info : An object is punted at 25 m/s (40° N of E) on a planet. acceleration due to gravity at that planet is 18 m/s².

To find : the range of the object on level of ground is...

solution : Range , R = u²sin2θ/g

here, angle made by object , θ = 40° N of E = 40° with horizontal..

initial velocity, u = 25 m/s

g = 18 m/s²

now, R = (25)²sin80°/18

= 625 × sin80°/18

= 34.2 m

Therefore the range of the object on level of ground is 34.2 m.

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Answer 2

Answer:

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