An object is put one by one in three liquids having
different densities. The object floats with 1/9;
2/11; 3/7 partsof their volumes outside the liquid
surface in liquids of densities d1; d2 and d3
respectively. Which of the following statement
is correct?
(1) d1>d2> d3 (2) d1>d2 <d3
(3)d1<d2>d3 (4) d1<d2<d3
PLEASE EXPLAIN ALSO!!
For 25 points!!!
Answers
the density of the liquid in this case depends upon the weight which it can with hold if it can with hold more weight its density is more if not its density is less therefore we we can indirectly see the volume which is immersed if the volume is much more that means the density is less and and liquid requires more area or volume to stop the resultant weight of the the object therefore it will submerge more if density is less......
in in this case we need to compare 1 by 9 2 by 11 3 by 7 which one is much more is having less density let's solve it
by calculation it came 3 by 7 is submerged the most then 2 by 11 then 9 by 11
therefore D3 the density of 3 by 7 is the least then D2 density of 2 by 11 is more than 3 by 7 but less than 1 by 9 and at last D1 density of nine by one is the most
<this calculation can only be done by a specific mass only and by the same object only dropped into the different liquids that mass of the the object cannot be changed>
thus answer comes to be=
D1>D2>D3...(1)[ans]
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