Physics, asked by yuvisingh85, 1 year ago

an object is released from a height .(a) find its speed at(1)t=1s(2)t=2sand(3)t=3s (b) find its distance travelled at (1)t=1s(2)t=2sand(3)t=3s

Answers

Answered by Prateek5304
23
g= 10m/s²
u=0m/s

(a) (1) t = 1s
a=( v-u)/ t
g= (v-0)
v= 10m/s
(2) t= 2s
v= 20m/s

(3) t = 3s
v= 30m/s

(b) (1) t= 1s
s= ut + 1/2 gt²
s= 0 + 1/2 *10 * 1*1
s= 5m

(2) t = 2s
s= ut + 1/2 gt²
s= 1/2*10*2*2
s= 20m

(3) t = 3s
s= ut + 1/2 gt²
s= 1/2 *10*3*3
s= 45m

hope it helps
Answered by studentofIndia896
5

a= 9.8m/s^2 : u= 0m/s^2

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