Question

An object is released from a height h above the
ground, reached the ground in 8 sec. The time
taken by the object to cover first half distance is
a) 222 sec
4/2s

Answer 1

Answer:4 seconds

Explanation:

displacement in t second is given by

St= u + 1/2*a*(2t-1)

S8 =0+1/2*10*(2*8-1)=75 m

I.e. In 8 second it  travels 75 m to reach the ground

now v=75/8 m/s

the half way distance is 75/2  m

half way time is T= 75/2*8/75=4 seconds