an object is released from an aircraft travelling horizontally with a constant velocity of 200m/s at a height of 500m.ignoring air resistance and taking g=10m/s².
a)how long it takes the object to reach the ground.
b)the horizontal distance covered by the object between leaving the aircraft and reaching the ground.
Answers
Answered by
6
(a) By the formula of time
t=(2h/g)^1/2 (t is time taken to come to earth)
h=500m
g=10m/s^2
putting value we get t=10second
(b)by the formula
R=ut (R is horizontal distance)
given
u=200m/s and t=10sec
putting value we get
R=2000metre
Answered by
0
Answer:2.5
Explanation: t=d/s
T=? D= 500 S=200
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