an object is released from some height exactly after one second another object is released from the same height the distance between the two object exactly after 2 second of the release of second object will be
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Answer:25 m
Explanation:
do this with s=at^2/2 formulae.
for first object,get 3s for time.
for second object,get 2s for time and get acceleration as 10ms^-2...so...you will get 25 m as the distance between the objects
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